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X^2-2/5X-16/5=0
Domain of the equation: 5X!=0We calculate fractions
X!=0/5
X!=0
X∈R
X^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{0}{2}=0$
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